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Question

Which term of the GP 1, 2, 4, 8,.... is 512?


A

8

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B

9

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C

10

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D

11

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Solution

The correct option is C

10


Given the GP: 1, 2, 4, 8, ......

a=1,r=2
The nth term of a GP of first term a and common ratio r is given by
an=arn1.
Let an=512.
Then, 1×2n1=512.
i.e., 2n1=29
n1=9
n=10


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