Which term of the sequence $3, 8, 13, 18, . . . . . . . .$ is $498$ .

95 t h

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100 t h

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102 t h

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101 t h

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Solution

The correct option is B $100 t h$
Given series is : $3, 8, 13, 18, . . . . . . . .$
$a = 3, l = 498, d = 5, n = ?$
$l = a + (n - 1) d$
$498 = 3 + (n - 1) 5$
$498 - 3 = (n - 1) 5$
$\frac{495}{5} = n - 1$
$∴ n = 99 + 1$
$∴ n = 100$
So $100^{t h}$ term is $498$

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