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Question

Which term of the sequence 4,9,14,19,.... is 124?

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Solution

Clearly, the given sequence is an A.P. with first term a(=4) and common difference d(=5)

Let 124 be the term of the given sequence. Then,

an=124
a+(n+1)d=124
4+(n1)×5=124
5n1=124
5n=125
n=25

Hence, 25th term of the given sequence is 124.

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