Which two of the following compounds belong to same homologous series- C 2 H 6 O 2- C 2 H 6 O - C 2 H 6- CH 4 OA- C 2 H 6 O - C 2 H 6 O 2B- C 2 H 6 O - CH 4 OC- CH 4 O - C 2 H 6 O 2D- C 2 H 6- CH 4 O

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Nomenclature of Alcohols

Which two of ...

Question

Which two of the following compounds belong to same homologous series? $C_{2} H_{6} O_{2}, C_{2} H_{6} O, C_{2} H_{6}, C H_{4} O$

$C_{2} H_{6} O$ & $C_{2} H_{6} O_{2}$

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$C_{2} H_{6} O$ & $C H_{4} O$

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$C H_{4} O$ & $C_{2} H_{6} O_{2}$

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$C_{2} H_{6}$ & $C H_{4} O$

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Solution

The correct option is B
$C_{2} H_{6} O$ & $C H_{4} O$

Two members of a homologous series differ from each other by - $C H_{2}$ group. Hence, $C H_{4} O$ and $C_{2} H_{6} O$ are from a homologous series.

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Similar questions

Q. What is a homologous series? Which two of the following organic compounds belong to the same homologous series?

C_{2} H_{6}, C_{2} H_{6} O, C_{2} H_{6} O_{2}, C H_{4} O

Q. How many compounds given below belong to the same homologous series?

{CH}_{2} O_{2}, C_{3} H_{8} O, C_{2} H_{4} O_{2}, C_{2} H_{6}, C_{3} H_{6} O_{2}, C_{4} H_{8} O_{2}

Q. The number of compounds given below that belong to same homologous series is ______.

{CH}_{2} O_{2}, C_{3} H_{8} O, C_{2} H_{4} O_{2}, C_{2} H_{6}, C_{3} H_{6} O_{2}, C_{4} H_{8} O_{2}

Q. The number of compounds given below that belong to same homologous series is ______.

{CH}_{2} O_{2}, C_{3} H_{8} O, C_{2} H_{4} O_{2}, C_{2} H_{6}, C_{3} H_{6} O_{2}, C_{4} H_{8} O_{2}

The number of compounds given below that belong to same homologous series are
$C H_{2} O_{2}, C_{3} H_{8} O, C_{2} H_{4} O_{2}, C_{2} H_{6}, C_{3} H_{6} O_{2}, C_{5} H_{10} O_{2}, C_{3} H_{8}$

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Which two of the following compounds belong to same homologous series? C2H6O2,C2H6O,C2H6,CH4O

The correct option is B C2H6O & CH4O Two members of a homologous series differ from each other by -CH2 group. Hence, CH4O and C2H6O are from a homologous series.

Which two of the following compounds belong to same homologous series? $C_{2} H_{6} O_{2}, C_{2} H_{6} O, C_{2} H_{6}, C H_{4} O$

The correct option is B
$C_{2} H_{6} O$ & $C H_{4} O$

Two members of a homologous series differ from each other by - $C H_{2}$ group. Hence, $C H_{4} O$ and $C_{2} H_{6} O$ are from a homologous series.