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Heterolytic Cleavage

Which type of...

Question

Which type of intermediate $(A)$ is formed during the reaction?
${C H}_{3} {C H}_{2} - N = N - {C H}_{2} {C H}_{3} h e a t - - \to (A) + N_{2}$

A

Carbocation

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B

Carbanion

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C

Free radical

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D

Carbene

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Solution

The correct option is B Free radical
$C H_{3} C H_{2} ∙ - ∙ N = N ∙ - ∙ C H_{2} C H_{3} h e a t - - \to 2 {C H_{3} C H_{2}}^{∙} A (Free Radical) + N \equiv N$

The homolytic bond fission takes p[lace and free radical intimidate is formed in the given reaction.
Hence, the correct option is $B$

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Similar questions

Q. Which amongst the following is a positional isomer of

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

Q. Match the column

A, B

C

Reactabts $(A)$	Products $(B)$	Name of the reaction $(C)$
$C H_{3} - C H_{3} + C l_{2}$	$C O_{2} + H_{2} O$	Addition reaction
$C_{2} H_{6} + O_{2}$	$C H_{2} = C H_{2}$	Thermal cracking
$_{n} C H_{2} = C H_{2}$	$C H_{2} = C H_{2} + C H_{4}$	Substitution reactions
$C H_{3} - C H_{2} - C H_{3}$	$C H_{3} - C H_{2} C l + H C l$	Polymerisation
$C H \equiv C H + H_{2}$	$[- C H_{2} - C H_{2} -]_{n}$	Combustion

Q. Assertion :When

C H_{3} - C H_{2} - C H_{2} - C H (B r) - C H_{3}

is treated with potassium tert-butoxide

C H_{3} - C H_{2} - C H_{2} - C H = C H_{2}

is formed. Reason: The above reaction is

E_{2}

.

Q. Identify the type of the following reaction of carbon compounds.
a. CH₃ -CH₂ -CH₂-OH → CH₃ -CH₂ -COOH
b. CH₃ -CH₂ -CH₃ → 3CO₂ + 4H₂O
c. CH₃ -CH = CH -CH₃ + Br₂ → CH₃ -CHBr - CHBr -CH₃
d. CH₃ -CH₃ + Cl₂→ CH₃ -CH₂ -Cl + HCl
e. CH₃-CH₂ -CH₂ -CH₂ -OH → CH₃ -CH₂ -CH=CH₂ + H₂O
f. CH₃-CH₂ -COOH + NaOH → CH₃ -CH₂ -COO - Na⁺ + H₂O
g. CH₃ -COOH + CH₃ -OH → CH₃ -COO- CH₃ + H₂O

Q. The compound B formed in the following sequences of reactions is

C H_{3} - C H_{2} - C H_{2} - C l (a) p r o p y l c h l o r i d e) A l c . K O H - ----- \to C H_{3} - C H = C H_{2} (P r o p e n e b)

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