Question

which type of the hybridisation of each of the carbon is there in the compound?
${CH}_3-CH=CH-CN$

• A. ${sp}^3,{sp}^2,{sp}^2,sp$
• B. ${sp}^3,{sp}^2,{sp}^2,{sp}^3$
• C. ${sp}^3,{sp}^2,{sp}^3,{sp}^3$
• D. ${sp}^3,{sp}^2,sp,{sp}^3$

Answer 1

Answer: (A)

${sp}^3,{sp}^2,{sp}^2,sp$

$C{H}_3-CH=CH-CN$

First carbon atom is $s{p}^3$ hybridised because it contains 4$\sigma$ bonds.

Second and third carbon atoms are $s{p}^2$ hybridised because it contains 3$\sigma$ bonds and 1$\pi$ bonds.

Fourth carbon atom is $sp$ hybridised because it contains 2$\sigma$ bonds and 2$\pi$ bonds.

Hence, option $A$ is correct.