Which will form 2,2-dibromopropane with HBr in presence of solvent CCl4?
A
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B
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C
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D
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Solution
The correct option is A Electrophilic addition of HBr with 2-bromopropene takes place according to markovnikov's rule to give 2,2-dibromopropane CH3−C|Br=CH2+HBrCCl4⟶CH3−Br|C|Br−CH3