Which will form maximum boiling point azeotrope?

H {N O}_{3} + H_{2} O

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C_{2} H_{5} O H + H_{2} O

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C_{6} H_{6} + C_{6} H_{5} {C H}_{3}

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None of these

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Solution

The correct option is A $H {N O}_{3} + H_{2} O$ solution
The solution (liquid mixtures) which boils at constant temperature can distil unchanged in composition are called azeotropes.
Solution of $H {N O}_{3}$ and $H_{2} O$ will form maximum boiling point azeotrope because they have a composition of having maximum boiling point. Maximum boiling azeotropes show negative deviation from Raoult's law
Composition(%) Boiling point
$H {N O}_{3}$ $68.0$ $359 K$
$H_{2} O$ $32.0$ $373 K$
Boiling point of the azeotrope of these two solutions is $393.5 K$

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C_{6} H_{6}, {C H}_{3} O H, C_{6} H_{5} {N H}_{2}

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C_{6} H_{6} \to C_{6} H_{5} {C H}_{3}

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C_{6} H_{5} O H + O_{3} ⟶ {C O}_{2} + H_{2} O + O_{2}

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