Which would undergo $S_{N} 1$ reaction faster in the following pair and why?
$C H_{3} - C H_{2} - B r and C H_{3} - C H_{3} | C | B r - C H_{3}$

Open in App

Solution

Reactivity in $S_{N} 1$ reaction depends upon the stability of carbocation intermediate formed after ionization of alkyl halide. Since $H_{3} C - C H_{3} | C | B r - C H_{3}$ will give more stable $3^{\circ}$ carbocation $⎛ ⎜ ⎜ ⎝ C H_{3} - C H_{3} | C + - C H_{3} ⎞ ⎟ ⎟ ⎠$ , therefore, it is more reactive than $C H_{3} C H_{2} - B r$ which upon ionization gives $1^{\circ}$ carbocation $(C H_{3} - {+ C H}_{2})$ of lesser stability.

Suggest Corrections

Similar questions

S_{N} 1

C H_{3} - C H_{2} - B r and C H_{3} - C H_{3} | C | B r - C H_{3}

S_{N} 1

C H_{3} - C H_{2} - C H_{2} - B r

C H_{3} - C H - C H_{3}

B r

S_{N} 1

{C H}_{3} - C H_{2} - B r

\begin{matrix} C H_{3} | C H_{3} & - & C & - & C H_{3} | B r \end{matrix}

Which would undergo $S_{N} 1$ reaction faster in the following pair and why?

$C H_{3} | C H_{3} - C H_{2} - B r a n d C H_{3} - C - C H_{3} | B r$

Which of the following compound would undergo SN1 reaction faster and why?

(C₆H₅)CH₂Cl. Or. (C₆H₁₁)CH₂Cl

Join BYJU'S Learning Program