Question

While a particle executes simple harmonic motion, the rate of change of acceleration is maximum and minimum, respectively at

• A. the mean position and extreme positions
• B. the extreme positions and mean positions
• C. the mean position alternatively
• D. the extreme position alternatively

Answer 1

The correct option is A the mean position and extreme positions

numerically, $a=w^{2}x.$
$\Rightarrow \frac{da}{dt}=w^2\frac{dx}{dt}$
$\Rightarrow \frac{da}{dt}=w^2\times w\sqrt{A^2-x^2}$
$\Rightarrow \frac{da}{dt}$ is maximum at x = 0 and minimum at x = A