While drawing a histogram for the discontinuous grouped data, if in case, the class intervals are given in the inclusive form, then in order to convert them into exclusive form, we must,

add the adjustment factor to all the lower limits to all upper limits.

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subtract the adjustment factor from all the lower limits and add it to all upper limits.

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subtract the adjustment factor from all the lower limits and from all upper limits.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

add the adjustment factor to all the lower limits and subtract it from all upper limits.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is B
subtract the adjustment factor from all the lower limits and add it to all upper limits.

While drawing a histogram for the discontinuous grouped data, if in case, the class intervals are given in the inclusive form, then in order to convert them into exclusive form, we must subtract the adjustment factor from all the lower limits and add it to all upper limits.

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Similar questions

If the classes in a grouped frequency distribution are not continuous, we can make them continuous by finding half of the difference between the upper limit of a class and the lower limit of the next class, and then adding the same to all the lower limits and subtracting it from all the upper limits in the distribution.

State true or false.

If the classes in a grouped frequency distribution are not continuous, we can make them continuous by finding the difference between the upper limit of a class and the lower limit of the next class, and then adding half of the difference to all the lower limits and subtract it from all the upper limits in the distribution.

The steps to convert an irregular class interval into a regular one, are

Step 1: Compute correction factor which is $\frac{upper class limit-lower class limit of previous class interval}{2}$ .

Step 2: This is added to the upper limit and subtracted from the lower limit of each class.

Fill in the blanks :
(i) Lower class limit of 15-18 is ___ .
(ii) Upper class limit of 24-30 is ___.
(iii) Upper limit of 5-12.5 is ___.
(iv) If the upper and the lower limits of a class interval are 16 and 10; the class interval is ___.
(v) If the lower and the upper limits of a class interval are 7.5 and 12.5; the class interval is ___.

The class midpoint is equal to:

(a) The average of the upper class limit and the lower class limit.

(b) The product of upper class limit and the lower class limit.

(d) None of the above.

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