MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Potassium Dichromate

While Fe2+ ...

Question

While $F e^{2 +}$ is stable, $M n^{3 +}$ is not stable in acid solution because ?

A

O_{2}

oxidises

M n^{2 +}

to

M n^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

O_{2}

oxidises both

M n^{2 +}

and

F e^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

F e^{3 +}

oxidises

H_{2} O

to

O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

M n^{3 +}

oxidises

H_{2} O

to

O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $M n^{3 +}$ oxidises $H_{2} O$ to $O_{2}$
$M n^{3 +}$ oxidises $H_{2} O$ to $O_{2}$ because the standard reduction potential of $(M n^{3 +} \to M n^{2 +})$ is greater than that of $(O_{2} \to H_{2} O$ ).

Suggest Corrections

thumbs-up

0

Similar questions

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

Q. Redox reactions play a pivotal role in chemistry and biology. The values of standard redox potential

(E_{⊖})

of two half cell reactions decided which way the reaction is expected to proceed. A simple example is a Daniell cell in which zinc goes into solution and copper gets deposited. Given below are a set of half cell reactions (acidic medium) along with their

E_{⊖}

(V with respect to normal hydrogen electrode) values. Using this data, obtain correct explanations for the following question

I_{2} + 2 e^{-} \to 2 I_{⊖}; E^{⊖} = 0.54

C l_{2} + 2 e^{-} \to 2 C I_{⊖}; E^{⊖} = 1.36

M n^{3 +} + e^{-} \to M n^{2 +}; E^{⊖} = 1.50

F e^{3 +} + e^{-} \to F e^{2 +}; E^{⊖} = 0.77

O_{2} + 4 H^{⨁} + 4 e^{-} \to 2 H_{2} I; E^{⊖} = 1.23

F e^{3 +}

M n^{3 +}

is not stable in acid solution because

Q. The standard reduction potential data at

25^{o} C

is given below:

E^{o} (F e^{3 +}, F e^{2 +}) = + 0.77 V

E^{o} (F e^{2 +}, F e) = - 0.44 V

E^{o} (C u^{2 +}, C u) = + 0.34 V

E^{o} (C u^{+}, C u) = + 0.52 V

E^{o} (O_{2} (g) + 4 H^{+} + 4 e^{-} \to 2 H_{2} O) = + 1.23 V

E^{o} (O_{2} (g) + 2 H_{2} O + 4 e^{-} \to 4 O H^{-}) = + 0.4 V

E^{o} (C r^{3 +}, C r) = - 0.74 V

E^{o} (C r^{2 +}, C r) = - 0.91 V

;
Which of the following statements is/are correct on the basis of above data:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Potassium Dichromate

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Potassium Dichromate

Standard IX Chemistry

Join BYJU'S Learning Program

CrossIcon