While F e 3- is stable- Mn 3- is not stabe in acid solution because- Mn 3- e - Mn 2- E -1-5 V - O 2-4 H -4 e - 2 H 2 O - E -1-23 V - F e 3- e - F e 2- E -0-77 V A- O2 oxidises Mn 2- and Fe 2- to Fe 3-B- Fe 3- oxidises H 2 O to O 2C- O2 oxidises Mn 2- to Mn 3-D- Mn 3- oxidises H 2 O to O 2

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Byju's Answer

Standard IX

Chemistry

Electrode Potential

While F e 3+ ...

Question

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

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Solution

The correct option is D
$M n^{3 +}$ oxides $H_{2} O$ to $O_{2}$ because the standard reduction potential of $(M n^{3 +} + e^{-} \to M n^{2 +}; E^{\circ} = + 1.5 V)$ is greater than that $(O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O; E^{\circ} = + 1.23 V)$

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Similar questions

Q. While

F e^{3 +}

is stable,

M n^{3 +}

is not stabe in acid solution because:

(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$