While finding the refractive index of a glass slab, the travelling microscope is focussed on ink dot on a white paper at position 4.320 cm. When a glass slab is placed on this ink dot on paper, the microscope is raised through 1.80 cm. The thickness of glass slab of refractive index $\frac{3}{2}$ is :

\frac{1}{0.8}

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2.70 cm

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5.4 cm

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1.2 cm

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Solution

The correct option is C 5.4 cm
shift $= t [1 - \frac{1}{μ}] 1.8 = t [1 - \frac{1}{3 / 2}] 1.8 = t \times \frac{1}{3} ∴ t = 5.4 c m$

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While finding the refractive index of a glass slab, the travelling microscope is focussed on ink dot on a white paper at position 4.320 cm. When a glass slab is placed on this ink dot on paper, the microscope is raised through 1.80 cm. The thickness of glass slab of refractive index 32 is :

The correct option is C 5.4 cmshift=t[1−1μ]1.8=t[1−13/2]1.8=t×13∴t=5.4cm

The correct option is C 5.4 cm
shift $= t [1 - \frac{1}{μ}] 1.8 = t [1 - \frac{1}{3 / 2}] 1.8 = t \times \frac{1}{3} ∴ t = 5.4 c m$