While finding the square root of 81 by repeated subtraction, in which step does 17 occur?
A
3rd
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B
5th
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C
8th
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D
6th
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Solution
The correct option is C 8th The sum of first n odd natural numbers is n2. This fact is used to find the square root of a number by repeated subtraction. In finding the square root of 81 by repeated subtraction the steps involved are:- StepNumberValue181−1=80280−3=77377−5=72472−7=65565−9=56656−11=45745−13=32832−15=17917−17=0 You can clearly see that 17 occurs in the 8th step.