While launching a rocket of mass $10^{4} k g$ , a force of $10^{6} N$ is applied for $10 s$ . What is the speed attained by the rocket at the end of $10 s$ ?

Open in App

Solution

Acceleration of rocket due to force $= \frac{F}{m} = \frac{10^{6}}{10^{4}} = 100 m / s^{2}$

Now, speed after 10 s can be found using first equation of motion $v = u + a t = 0 + 100 \times 10 = 1000 m / s$

Suggest Corrections

Similar questions

Q. While launching a rocket of mass

2 \times 10^{4}

kg, the

5 \times 10^{5} N

is applied for

20 s

. Calculate the velocity attained by the rocket at the end of

20 s

Q. A rocket is going upwards with accelerated motion. A man sitting in it feels his weight increased 5 times his own weight. If the mass of the rocket including that of the man is

1.0 \times 10^{4} k g

, how much force is being applied by rocket engine?

Q. The driver of a car moving towards a rocket launching pad with a speed of 6

m s^{- 1}

observed that the rocket is moving with a speed of 10

m s^{- 1}

the upward speed of the rocket as seen by the stationary observer is

A rocket is launched vertically from the surface of the earth of radius R with an initial speed v. If atmospheric resistance is neglected, the maximum height attained by the rocket is given by

Q. The exhaust velocity of the gases coming out of a rocket is

350 m/s

w.r.t the rocket. The rocket can burn fuel at a rate of

80 kg/s

. For a successful launch, the desired acceleration of the rocket is

4 {m/s}^{2}

. What is the initial total mass of this rocket? (Take

g = 10 {m/s}^{2}

)

Join BYJU'S Learning Program

While launching a rocket of mass 104 kg, a force of 106 N is applied for 10s. What is the speed attained by the rocket at the end of 10s?

Acceleration of rocket due to force =Fm=106104=100m/s2Now, speed after 10 s can be found using first equation of motion v=u+at=0+100×10=1000m/s

While launching a rocket of mass $10^{4} k g$ , a force of $10^{6} N$ is applied for $10 s$ . What is the speed attained by the rocket at the end of $10 s$ ?

Acceleration of rocket due to force $= \frac{F}{m} = \frac{10^{6}}{10^{4}} = 100 m / s^{2}$

Now, speed after 10 s can be found using first equation of motion $v = u + a t = 0 + 100 \times 10 = 1000 m / s$