While measuring the diameter of a sphere with a vernier calipers if MSR and VCD are 35 mm and 5 respectively and if the vernier scale consists of 20 divisions and 1 MSD is 1 mm then what is the diameter of the sphere?

64.35 mm

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35.25 mm

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1.95 mm

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4.25 mm

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Solution

The correct option is B 35.25 mm
Number of division on main scale $n = 10$
Number of division on vernier scale $m = 20$
Main scale division $1 M . S . D . = 1 m m$
Least count of vernier caliper $L . C . = M . S . D . \times \frac{n}{m} = 1 m m \times \frac{10}{20} = 0.5 m m$
Main scale reading $M . S . R . = 35 m m$
Coinciding division $n_{1} = 5$
Diameter of wire $d = M . S . R . + n_{1} \times L . C . = 35 + 0.5 \times 0.5 = 35.25 m m$

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