While measuring the length of an instrument, main scale reading is 5.2 cm and seventh division on vernier scale is in line with a marking on the main scale. If the zero error is 0.03 cm, then length of the instrument isWhile measuring the length of an instrument, main scale reading is 5.2 cm and seventh division on vernier scale is in line with a marking on the main scale. If the zero error is 0.03 cm, then length of the instrument is

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Solution

Dear student,

$G i v e n : A s s u m i n g L e a s t C o u n t (L . C .) o f v e r n i e r = 0.01 c m M a i n s c a l e r e a d i n g (M . S . R) = 5.2 c m 7^{t h} v e r n i e r d i v i s i o n c o i n c i d i n g w i t h m a i n s c a l e m a r k i n g T h e r e f o r e V e r n i e r S c a l e R e a d i n g (V . S . R .) = 7 \times L . C . = 7 \times 0.01 = 0.07 c m Z e r o e r r o r = + 0.03 T h e r e f o r e, l e n g t h o f t h e i n s t r u m e n t = [M . S . R + V . S . R] - Z e r o e r r o r = [5.2 + 0.07] - 0.03 5.24 c m$

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