While measuring the length of the rod by vernier callipers the reading on main is 6.4 cm and the eighth division on vernier is in line with marking on the main division. If the least count of callipers is 0.01 cm and zero error-0.04 cm, find

6.52 m

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6.52 cm

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6.52 mm

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0.652 mm

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Solution

The correct option is A 6.52 mm
$\begin{matrix} Final reading = & MSR + VSR - zero error \end{matrix}$

$\begin{matrix} = & 6.4 + (coinciding \times L \cdot C) - (- 0.04) = & 6.44 + (8 \times 0.01) = 6.44 + 0.08 = 6.52 m m \end{matrix}$

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