While measuring the zero error of a vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with $6^{t h}$ vernier division coinciding with main scale division. If the least count of the vernier is 0.1 mm, then find its zero error.

Zero error = 6 mm

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Zero error = 6 cm

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Zero error = 0.6 mm

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Zero error = 0.6 cm

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Solution

The correct option is C Zero error = 0.6 mm
L.C. = 0.1 mm

Given while measuring Zero error, zero of vernier is to right of main scale 0. So when the scale should have read 0 it was actually reading 0+6 L.C.

Zero error = $6 \times 0.1 m m = 0.6 m m$

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Similar questions

Q. While measuring the zero error of a vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with

6^{t h}

vernier division coinciding with main scale divisions. If the least count of the vernier is 0.1 mm then find its zero error and the correction reuired in the measurements made by it.

Q. While measuring the zero error of a vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with

6^{t h}

vernier division coinciding with main scale divisions. If the least count of the vernier is 0.1 mm then find its zero error and the correction reuired in the measurements made by it.

Q. Consider the following data for a vernier calliper:
10 main scale division = 1 cm.
10 vernier division matches with 9 Main scale division.

While measuring the zero error of the vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with

6^{t h}

vernier division coinciding with main scale divisions.

The actual reading for length measurement is 4.3 cm with 2nd vernier division coinciding with main scale graduation.

Estimate the length.

Consider the following data: 10 main scale division = 1cm, $10^{t h}$ vernier division match with $9^{t h}$ Main scale division. While measuring the zero error of the vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with $6^{t h}$ vernier division coinciding with main scale divisions. The actual reading for length measurement is 4.3 cm with 2nd vernier division coinciding with main scale graduation. Estimate the length.

Q. In an experiment to find zero error of vernier caliper, it is found that zero of vernier scale is left to zero of main scale and

4^{t h}

division of vernier matches with a division on main scale. Given that 9 division of main scale is equal to 10 division of vernier and one division of main scale is 1 mm. Then zero error with sign is

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While measuring the zero error of a vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with 6th vernier division coinciding with main scale division. If the least count of the vernier is 0.1 mm, then find its zero error.

The correct option is C Zero error = 0.6 mmL.C. = 0.1 mm Given while measuring Zero error, zero of vernier is to right of main scale 0. So when the scale should have read 0 it was actually reading 0+6 L.C. Zero error = 6×0.1 mm=0.6 mm

While measuring the zero error of a vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with $6^{t h}$ vernier division coinciding with main scale division. If the least count of the vernier is 0.1 mm, then find its zero error.

The correct option is C Zero error = 0.6 mm
L.C. = 0.1 mm

Given while measuring Zero error, zero of vernier is to right of main scale 0. So when the scale should have read 0 it was actually reading 0+6 L.C.

Zero error = $6 \times 0.1 m m = 0.6 m m$