While moving with uniform acceleration, a body has covered 550m in 10 second and attained a velocity of 105ms−1. Its initial velocity u and acceleration a respectively are
A
10ms−1,5ms−2
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B
10ms−1,−5ms−2
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C
5ms−1,10ms−2
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D
10ms−1,0ms−2
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Solution
The correct option is C5ms−1,10ms−2 v=u+at 105=u+10a.....(1) 550=u(10)+12×a×102 ⇒550=10u+50a⇒55=u+5a.....(2) eqn(1)−eqn(2) ⇒50=5a a=10m/s2 u=5m/s