While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:

Mass of water in the beaker = 40 g

Mass of raisins before soaking = 5 g

Mass of raisins after soaking for 2 hours = 8 g

Mass of water left in the beaker after the experiment = 35 g

The percentage of water absorbed by raisins is:

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Solution

The correct option is D

The percentage of water absorbed by raisins is calculated by using the formula
$\frac{W_{2} - W_{1}}{W_{1}} \times 100$
where, $W_{2}$ is the weight of wet raisin and W₁ is the weight of dry raisin.
The Correct Answer is D

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Similar questions

Q. The following data was obtained on performing an experiment for determining the percentage of water absorbed by raisins:

Mass of water in the beaker	=	50 g
Mass of dry raisins	=	20 g
Mass of raisins after soaking in water	=	30 g
Mass of water left in the beaker after the experiment	=	40 g

The percentage of water absorbed by raisins will be:

(1) 10%
(2) 25%
(3) 45%
(4) 50%

Ram soaked 8g of raisins in water and after 4 hours found that their mass has been 12g . Determine the percentage of water absorbed by raisins.

Q. A student soaked 5 g of raisins in beaker (A) containing 25 mL of ice-chilled water and another 5 g of raisins in beaker (B) containing 25 mL of tap water at room temperature. After one hour the student observed that:
(1) water absorbed by raisins in beaker (A) was more than that absorbed by raisins of beaker (B).
(2) water absorbed by raisins in beaker (B) was more than that absorbed by raisins of beaker (A).
(3) the amount of water absorbed by the raisins of both beakers (A) and (B) was equal.
(4) no water was absorbed by raisins in either of the beakers (A) and (B).

Q. a student recorded the mass of dry raisins is 6.0 g and mass of raisins after soaking them in water in 10.5 g. calculate the percentage of water absorbed by raisins.

Dry raisins were soaked in water for 2 hours, to determine the percentage of water absorbed by raisins. Before final weighing of swollen raisins, the extra water left on the surface of soaked raisins was removed by:

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The correct option is D The percentage of water absorbed by raisins is calculated by using the formula W2−W1W1×100 where, W2 is the weight of wet raisin and W1 is the weight of dry raisin. The Correct Answer is D

The correct option is D

The percentage of water absorbed by raisins is calculated by using the formula
$\frac{W_{2} - W_{1}}{W_{1}} \times 100$
where, $W_{2}$ is the weight of wet raisin and W₁ is the weight of dry raisin.
The Correct Answer is D