Question

While removing material from iron (atomic weight = 56, valency = 2 and density = 7.8 g/cc by electrochemical machining, a metal removal rate of 2 cc/min is desired. The current (in A) required for achieving this material removal rate is

• A. 896.07
• B. 14.93
• C. 448.03
• D. 53764.29

Answer 1

The correct option is A 896.07

$MRR=\frac{AI}{\rho ZF}$

$\Rightarrow \frac{2}{60}cc/s=\frac{56\times I}{7.8\times 2\times 96500}$

$\Rightarrow I=\frac{7.8\times 2\times 96500\times 2}{60\times 56}A$

$=896.07A$