Question

While selling a router, a shopkeeper gives a discount of $15\%.$ If he gives a discount of $20\%,$ he earns $Rs.51$ less as profit. What is the original marked price of the router?

Answer 1

Let the marked price of the router be $x.$

If shopkeeper gives a discount of $15\%$ then

$S{P}_1=x-\frac{15}{100}x$

$=\frac{85x}{100}$

If shopkeeper gives a discount of $20\%$ then

$S{P}_2=x-\frac{20}{100}x$

$=\frac{80x}{100}$

So, according to question

$\begin{array}{cc}S{P}_1-S{P}_2& =51\\ \frac{85x}{100}-\frac{80x}{100}& =51\\ \frac{5x}{100}& =51\\ \frac{x}{20}& =51\\ x& =Rs.1020\end{array}$

Hence, the original marked price of the router is equal to $Rs.1020.$