While solving a question tan x = √3 I got the principal solution as π/3 and 4π/3... So can x=nπ+4π/3 be the general solution of it or only x=nπ+π/3 can be the general solution of it ...as given in book.
Open in App
Solution
Principal Value of inverse tan is between -Pi/2 and Pi/2.
So When tan x = sqrt(3) , We get x= Pi/3 as principal value.
So The general solution is x = n * Pi + Pi/3.
Don't worry about 4Pi/3 . When n=1 in the general solution , We get 4Pi/3.