While testing borate, green edged flame is due the to formation of:

(C_{2} H_{5} O)_{3} N

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(C_{2} H_{5} O)_{3} O

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(C_{2} H_{5} O)_{3} N O_{2}

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(C_{2} H_{5} O)_{3} S O_{4}

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(C_{2} H_{5} O)_{3} B

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Solution

The correct option is C $(C_{2} H_{5} O)_{3} B$
While testing borate, green edged flame is due to the formation of triethyl borate, as shown in the image attached.

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C_{2} H_{5} - O - N = O

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S - S

C_{2} H_{5} - S - C_{2} H_{5}; Δ H_{f}^{o} = - 147 k J {m o l}^{- 1}

C_{2} H_{5} - S - S - C_{2} H_{5}; Δ H_{f}^{o} = - 201.9 k J {m o l}^{- 1}

S (g) - Δ H_{f}^{o} = - 222.8 k J {m o l}^{- 1}

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{Δ H}_{f o r m}^{o} (C_{2} H_{5} O H) = - 235.3 K J / m o l

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