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Byju's Answer

Standard XII

Chemistry

Allotropes of Phosphorus

White phospho...

Question

White phosphorous $(P_{4})$ has:

four

P - P

single bonds

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four lone pair of electrons

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P - P - P

angle of

60^{o}

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light

P - P

single bonds

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Solution

The correct options are
B four lone pair of electrons
C $P - P - P$ angle of $60^{o}$
$P_{4}$ molecule
Bond angle $= 60^{o}$
Six P - P $=$ single bond
Lone pair $=$ 4 in each molecule

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Similar questions

White phosphorus $P_{4}$ has

Q. Single

N - N

bond is weaker than the single

P - P

bond. This is because of:

Q. The average energy required to break a P - P bond in

P_{4} (s)

into gaseous atoms is

53.2 k c a l m o l^{- 1} .

The bond dissociation energy of

H_{2} (g)

104.2 k c a l m o l^{- 1}; △_{f} H^{o}

P H_{3} (g)

from

P_{4} (s)

5.5 k c a l m o l^{- 1} .

The P - H bond energy in

k c a l m o l^{- 1}

is [Neglect presence of van der Waals forces in

P_{4} (s)

]
Given:

P_{4} (s)

contains

6 P - P

single bonds.

Q. Atomicity of white or yellow phosphorus is 4 and it forms a molecule

- P_{4}

. Calculate the value of the expression

\frac{x . y}{z}

, where:

x

: Total number of vertex angles in

P_{4}

molecule

y

: Total number of lone pairs in

P_{4}

molecule

z

: Total number of

P - P

bonds in

P_{4}

molecule

P_{4} S_{3}

has 6

P - S

and ___

P - P

bonds.

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White phosphorous (P4) has:

The correct options are B four lone pair of electrons C P−P−P angle of 60oP4 moleculeBond angle =60oSix P - P = single bondLone pair = 4 in each molecule

White phosphorous $(P_{4})$ has:

The correct options are
B four lone pair of electrons
C $P - P - P$ angle of $60^{o}$
$P_{4}$ molecule
Bond angle $= 60^{o}$
Six P - P $=$ single bond
Lone pair $=$ 4 in each molecule