Why are colourless gas bubbles evolved when calcium reacts with cold water?
And also when metals react with dil.acids?

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Solution

Dear student,

When calcium is added to cold water, it reacts with water to form hydrogen gas which is evolved as colourless gas.
Ca + H2O ---> CaO + H2(g)

Metal reacts with acid to form colourless hydrogen gas as,
2M + 2HCl ---> 2MCl +H2 (g)

Regards

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Similar questions

Q. Statement I:- Hydrogen gas is not evolved when zinc reacts with cold water.

Statement II:- Sodium reacts vigorously with cold water to produce sodium hydroxide and hydrogen gas.

Q. When metal X reacts with dilute

HCl

, bubbles of gas Y are formed. Moreover, when this metal X reacts with cold water, it will again produce gas Y. Identify X and Y.

(a) Name a metal for each case:
(i) it does not react with cold as well as hot water but reacts with steam.
(ii) It does not react with any physical state of water.

(b) When calcium metal is added to water, the gas evolved does not catch fire but the same gas evolved on adding sodium metal to water catches fire. Why is it so?

Q. When metal X reacts with dilute

HCl

then bubbles of gas Y are formed. Moreover, when this metal X reacts with cold water it will again produce this gas Y. Identify X and Y.

Which gas is evolved when sodium metal reacts with water?

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Why are colourless gas bubbles evolved when calcium reacts with cold water? And also when metals react with dil.acids?

Dear student, When calcium is added to cold water, it reacts with water to form hydrogen gas which is evolved as colourless gas. Ca + H2O ---> CaO + H2(g) Metal reacts with acid to form colourless hydrogen gas as, 2M + 2HCl ---> 2MCl +H2 (g) Regards

Why are colourless gas bubbles evolved when calcium reacts with cold water?
And also when metals react with dil.acids?

Dear student,

When calcium is added to cold water, it reacts with water to form hydrogen gas which is evolved as colourless gas.
Ca + H2O ---> CaO + H2(g)

Metal reacts with acid to form colourless hydrogen gas as,
2M + 2HCl ---> 2MCl +H2 (g)

Regards