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Potentiometer

Why do equipo...

Question

Why do equipotential surfaces exist even though potential falls by 1/r relation?

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Solution

$O n t h e g i v e n s u r f a c e p r e s u m e d t o b e e q u i p o t e n t i a l s u r f a c e, o n s u c h s u r f a c e e l e c t r i c p o t e n t i a l a l l o v e r i t s s u r f a c e i s c o n s \tan t . I n o t h e r w o r d s p o t e n t i a l d i f f e r e n c e i s z e r o . T h e r e l a t i o n w h i c h h o l d s f o r p o t e n t i a l d i f f e r e n c e i s V α \frac{1}{r} W h e n w e m o v e s l i g h t l y u p o r d o w n o r i n o r o u t o f t h e e q u i p o t e n t i a l s u r f a c e t h e v a l u e o f p o t e n t i a l d i f f e r e n c e w i l l c h a n g e .$

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Similar questions

Q. Write two properties of equipotential surfaces. Depict equipotential surfaces due to an isolated point charge. Why do the equipotential surfaces get closer as the distance between the equipotential surface and the source charge decreases ?

Q. Define an equipotential surface. Draw equipotential surfaces :

(i) in the case of a single point charge and
(ii) in a constant electric field in Z-direction.

Why the equipotential surfaces about a single charge are not equidistant ?
(iii) Can electric field exist tangential to an equipotential surface ? Give reason.

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component of electric field is given by,

E_{x} = - \frac{δ V}{δ x}

and on equipotential surface potential

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Q. Question 22
The earth is acted upon by gravitation of Sun, even though it does not fall into the Sun. Why?

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