Why does a bulb when connected to a battery glows but not the wire connecting the two?

The bulb filament has lesser resistance

No worries! We‘ve got your back. Try BYJU‘S free classes today!

More current flows through the bulb

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The bulb filament has more resistance

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Less current flows through the bulb

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
The bulb filament has more resistance

The bulb filament has more resistance so we get more light while the connecting wire has very less resistance.

Suggest Corrections

Similar questions

Q. The same amount of current flows through the connecting wires and the bulb filament. However, it is only the filament that glows. Why?

A car bulb connected to a 12 volt battery draws 2 A current when glowing. What is the resistance of the filament of the bulb? Will the resistance be more, same or less when the blb is not glowing?

Q. When current is passed through an electric bulb, its filament glows, but the wire leading current to the bulb does not glow because :

Q. A car bulb connected to a 12 volt battery draw 2 A current when glowing. What is the resistance of the filament of the bulb?

Q. A 12-volt battery is connected to two light bulbs, as drawn in figure 1 light bulb 1 has resistance 3 ohms, while light bulb 2 has resistance 6 ohms. The battery has essentially no internal resistance, and all the wires are essentially resistanceless, too. When a light bulb is unscrewed, no current flows through that branch of the circuit. For instance, if light bulb 2 is unscrewed, current flows only around the lower loop of the circuit, which consist of the battery and light bulb 1. The more current flows through a light bulb, their equivalent resistance is

R_{e q} = R_{1} + R_{2}

. By contrast, when two reisistors are wired in parallel, their net resisance is given by

\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}

Bulb 2 is now screwed in as a result, bulb 1 :

Join BYJU'S Learning Program

Why does a bulb when connected to a battery glows but not the wire connecting the two?

The correct option is C The bulb filament has more resistance The bulb filament has more resistance so we get more light while the connecting wire has very less resistance.

The correct option is C
The bulb filament has more resistance

The bulb filament has more resistance so we get more light while the connecting wire has very less resistance.