Why does a glass tumbler containing ice-cool drinks show droplets of water on its outer surface?

Water vapour present in the atmosphere condense to form clews on it

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This is due to the difference of temperature between inside and outside of the glass

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Tiny holes between the glass molecules help the liquid to ooze out

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Difference in temperatures between ice-cool drinks and air outside glass increases the relative humidity

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Solution

The correct option is A Water vapour present in the atmosphere condense to form clews on it
Sometimes, We see water droplets on the outer surface of ice-cold water, this is because water vapour present in atmosphere gets converted to liquid state when vapours come in contact with cold glass of water.

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Similar questions

Q. Statement I: Water droplets form on the outside of a beaker containing an ice bath.
Statement II: Water vapor molecules in the air lose energy when they collide with the cold glass surface and condense.

Q. Sunita dropped some ice cubes into a glass tumbler. After a while she saw two changes. Which of the following statements tell you what she might have observed?
A. The ice melted which is a physical change.
B. She saw droplets of water forming on the outside of the glass tumbler due to evaporation.
C. She saw droplets of water forming on the outside of the glass tumbler due to water vapour in the air condensing on it.
D. Condensation of water vapour is a physical change.
E. Formation of droplets is a chemical change as a new substance is formed.
F. The melting ice takes up heat from the surroundings.

(a) A, C, E, F are true.
(b) A, B, C, D are true.
(c) C, D, E, F are true.
(d) A, C, D, F are true.

Q. Water droplets are formed on the outer surface of a glass containing ice-cold water. Why?

A glass contains some water at room temperature $20^{0}$ C. Refrigerated water is added to it slowly. When the temperature of the glass reaches $10^{0}$ C, small droplets condense on the outer surface. Calculate the relative humidity in the room. The boiling point of water at a pressure of 17.5 mm of mercury is $20^{0}$ C and at 8.9 mm of mercury it is $10^{0}$ C.

Q. A glass contains some water at room temperature 20°C. Refrigerated water is added to it slowly. when the temperature of the glass reaches 10°C, small droplets condense on the outer surface. Calculate the relative humidity in the room. The boiling point of water at a pressure of 17.5 mm of mercury is 20°C and at 8.9 mm of mercury it is 10°C.

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