Why does a Lever of second-order have a mechanical advantage of more than 1?

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Solution

Explanation
In the second class lever, the load is situated in between effort and fulcrum.
Hence, the effort arm is bigger than the load arm.

The mechanical advantage of a lever of the second order is always greater than one because its effort arm is always longer than the load arm i.e. Effort arm > Load arm
Since $M e c h a n i a l a d v a n t a g e = \frac{E f f o r t a r m}{L o a d a r m}$
The numerator is greater than the denominator, therefore MA is >1
In other words, a class 2 lever always acts as a force multiplier which is less effort is needed to overcome a large load

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