Question

Why does $BeC{l}_2$ violate the octet rule?

Answer 1

Octet Rule:

1. By making covalent connections and gaining or losing electrons from its outermost shell, an atom tends to have eight electrons in its outermost valence shell, according to the octet rule.
2. The main group elements, oxygen, carbon, and nitrogen, follow the octet laws. Except for lithium, hydrogen, and helium, all s-block and p-block elements adhere to the octet rule.

The number of electrons in Beryllium in BeCl₂:

The Be atom has two valence electrons, while the Cl atom has seven. BeCl₂ has a total of 2+7+7=16 valence electrons.

Beryllium chloride $\left(BeC{l}_2\right)$:

1. Beryllium chloride does have the structure $BeC{l}_2$ which is an inorganic chemical.
2. It's a colourless, hygroscopic solid that dissolves easily in a wide range of polar solvents.
3. Because of beryllium's diagonal connection with aluminium, its characteristics are comparable to those of aluminium chloride.

The Octet Rule Violate in $BeC{l}_2$:

1. Because the boron should be in a valence state that allows it to bind to three chlorines, $BeC{l}_2$ breaks the octet rule.
2. However, the boron is connected with six electrons in this molecule.