Why does butan2one + NH2OH give 2 oxime other than one oxime ?

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Solution

The two oximes are due to the two directions of the incoming group. One, when it attacks on the methyl group, and the other one from the side of ethyl group.

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Similar questions

Which of the following will form only one oxime on reaction with $N H_{2} O H$ solution?

N H_{2} O H

N H_{2} O H

N H_{2} O H

Why does compound (A) given below not form an oxime?

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