why does the gravitational force becomes one fourth when we double the distance between two objects??

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Solution

$S i n c e, F = \frac{G m_{1} m_{2}}{r^{2}} I n t h e I I n d c a s e r' = 2 r S o, F' = \frac{G m_{1} m_{2}}{(2 r)^{2}} = \frac{G m_{1} m_{2}}{4 r^{2}} = \frac{F}{4}$

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