Why $H_{2} {S O}_{4}$ cannot be used along with KI in the conversion of an alcohol to an alkyl iodide?

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Solution

In presence of sulfuric acid, $K I$ produce $H I$ .
$2 K I + H_{2} {S O}_{4} \to 2 K H {S O}_{4} + 2 H I$
Since, $H_{2} {S O}_{4}$ is oxidising agent, it oxidises $H I$ .
$2 H I + H_{2} {S O}_{4} \to I_{2} + {S O}_{2} + H_{2} O$
As a result, the reaction between alcohol and $H I$ to produce alkyl iodine cannot occur. Therefore sulphuric acid can't be used.

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