Why $H_{3} P O_{4}$ is triprotic acid but $H_{3} P O_{3}$ is diprotic acid?

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Solution

Due to more electronegativity difference between $H$ and $O$ , the $H$ atom attached to $O$ atom is released when the acid is dissolved in water.
$H_{3} P O_{3}$ has $2 P - O H$ bonds while $H_{3} P O_{4}$ has $3 P - O H$ bonds.
Hence $H_{3} P O_{4}$ is triprotic acid but $H_{3} P O_{3}$ is diprotic acid.

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$H_{3} P O_{2}$ and $H_{3} P O_{3}$

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Why $H_{3} P O_{4}$ is a tribasic and $H_{3} P O_{3}$ is a dibasic acid?

H_{3} P O_{4}

is a weak triprotic acid. The approximate

p H

0.1 M N a_{2} H P O_{4} (a q .)

is calculated by

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Why H3PO4 is triprotic acid but H3PO3 is diprotic acid?

Due to more electronegativity difference between H and O, the H atom attached to O atom is released when the acid is dissolved in water.H3PO3 has 2P−OH bonds while H3PO4 has 3P−OH bonds.Hence H3PO4 is triprotic acid but H3PO3 is diprotic acid.

Why $H_{3} P O_{4}$ is triprotic acid but $H_{3} P O_{3}$ is diprotic acid?