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Question

why hydrogen fluoride has much higher molecular mass than its molecular mass calculated by it's formula?

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Solution

This is because of the high density of HF in the gas phase as a result of hydrogen bonding between the molecules.

According to the ideal gas equation PV = nRT

​PV = (m/M)RT where m is the mass of the gas and M is the molecular mass

PM = (m/V)RT

PM = dRT density d = mass/volume or m/V

Molecular mass M is directly proportional to the density d

You can see that a higher value of density will result in a higher molecular mass. Therefore, the molecular mass obtained by the above equation is much higher than that calculated by the molecular formula.



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