Dear Student,
Let L be the load lifted by an effort E, Such that T is the tension in the rope
Then L = T…..(1)
And E = T……(2)
Or L = E
i.e. L/E = 1
or Mechanical effort = Load/Effort = 1
Let d be the distance through which effort acts, as well as load lifted
Then Velocity Ratio = Distance through which effort moves/Distance through which load moves
Velocity Ratio = d/d = 1
So Mechanical effort = Velocity Ratio
However a part of effort is wasted in moving the single fixed pulley around its axis and due to friction between the rope and pulley. Thus effort is able to lift less load than actual effort applied and hence mechanical advantage is less than 1.
Regards.