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why is 2 the ...

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why is 2 the n factor of H_3PO_{4 }

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n -

P_{4} O_{6}

P_{4} O_{6} ⟶ H_{3} P O_{4}

Q. Assertion: In the reaction:

2 N a O H + H_{3} P O_{4} \to N a_{2} H P O_{4} + 2 H_{2} O

The Equivalent weight of

H_{3} P O_{4}

\frac{M}{3}

, where M is its molar mass
Reason: Equivalent weight

= \frac{Molar mass}{n-factor}

Q. How to calculate the n factor of HCL, HNO3 and H3PO4?

What is the acidic strength order of $H_{3} P O_{2}$ , $H_{3} P O_{3}$ , $H_{3} P O_{4}$ ? Why ?

Q. The value of

p

which will make

2 m^{2} + p m n + 3 n^{2} - 5 n - 2

equivalent to the product of two linear factors is

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