why is a short wavelength or high frequency of light more suitable for photoelectric effect?

Open in App

Solution

$D e a r s t u d e n t, S h o r t w a v e l e n g t h o r H i g h e r - f r e q u e n c y p h o t o n s h a v e m o r e p o w e r, i n o r d e r t h a t t h e y m u s t c r e a t e t h e e l e c t r o n s c o m e b a c k f l y i n g o u t f a s t e r; t h u s, s w i t c h t o l i g h t w i t h t h e e q u a l d e p t h h o w e v e r a b e t t e r f r e q u e n c y m u s t g r o w t h t h e m o s t k i n e t i c p o w e r o f t h e e m i t t e d e l e c t r o n s . R e g a r d s$

Suggest Corrections

Similar questions

For photoelectric emission, tungsten requires light of $2300 \circ A$ . If light of $1800 \circ A$ wavelength is incident then emission

Join BYJU'S Learning Program