Why is be solubility of $N a C l$ in water $311 g l^{- 1}$ $N$ but is zero in benzene?

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Solution

$N a C l$ is an ionic compound and soluble only in the polar solvent because we know that "like dissolve like", water is a polar solvent and benzene is a non-polar solvent,
hence, the solubility of NaCl in water is $311 g l^{- 1}$ and zero in benzene.

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