Why is electronegativity directly proportional to $s$ character?

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Solution

S orbital being nearer to the nucleus, the electron pair of bond will be more attracted towards nucleus. So hybrid orbitals having more S-character are attached more towards nucleus showing higher electro-negativity.

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The only correct combination for the energy involved during the gain of an electron is:

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Why is electronegativity directly proportional to s character?

S orbital being nearer to the nucleus, the electron pair of bond will be more attracted towards nucleus. So hybrid orbitals having more S-character are attached more towards nucleus showing higher electro-negativity.

Why is electronegativity directly proportional to $s$ character?