Question

Why is pure $NaCl$ precipitated when $HCl$ gas is passed in saturated solution of $NaCl$?

• A. Impurities dissolve in $HCl$
• B. The value of $\left[{Na}^{+}\right]$ and $\left[{Cl}^{-}\right]$ products becomes smaller than $K_{sp}$ of $NaCl$.
• C. The value of $\left[{Na}^{+}\right]$ and $\left[{Cl}^{-}\right]$ products becomes higher than $K_{sp}$ of $NaCl$
• D. $HCl$ dissolves in water

Answer 1

Answer: (C)

The value of $\left[{Na}^{+}\right]$ and $\left[{Cl}^{-}\right]$ products becomes higher than $K_{sp}$ of $NaCl$

Pure $NaCl$ is precipitated because when $HCl$ gas is passed in saturated solution of $NaCl$ the concentration of $C{l}^{-}$ increases so reaction will move in backward direction and precipitation of $NaCl$ will start.