Why is resistance less when resistors are joined in parallel?

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Solution

We know that $\frac{1}{R} = \frac{1}{r_{1}} + \frac{1}{r_{2}}$
In parallel combination of resistors, the effective area of cross-section of the conductor increases, to the resistance decreases.

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Why is resistance less when resistors are joined in parallel?

We know that 1R=1r1+1r2In parallel combination of resistors, the effective area of cross-section of the conductor increases, to the resistance decreases.

We know that $\frac{1}{R} = \frac{1}{r_{1}} + \frac{1}{r_{2}}$
In parallel combination of resistors, the effective area of cross-section of the conductor increases, to the resistance decreases.