why is the spring watch not affected by the variation of g whereas pendulum is affected?

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Solution

Dear Student,
$T i m e p e r i o d o f p e n d u l u m = 2 π \sqrt{\frac{l}{g}} W h e r e a s T i m e p e r i o d o f s p r i n g w a t c h = 2 π \sqrt{\frac{m}{k}} s o t i m e p e r i o d o f p e n d u l a m d e p e n d s u p o n g b u t s p r i n g w a t c h n o t t h a t i s w h y t i m e p e r i o d o f s p r i n g w a t c h d o n o t a f f e c t e d b y v a r i a t i o n o f g$
Regard

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