Question

Why is the weight of an object on the surface of the moon $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$6^{\mathrm{th}}$}\right.$ its weight on the earth?

Answer 1

Explanation

1. The moon's mass is $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$100$}\right.$ that of the earth, while its radius is $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$4$}\right.$ that of radius. As a result, the moon's gravitational attraction is about one-sixth that of Earth.
2. The moon is significantly less massive and has a different radius(R) than the Earth.
3. The gravitational force of the moon is influenced by its mass and size. As a result, the weight of an object on the moon is 1/6 that of an object on Earth.