Question

Why $PbC{l}_4$ exist but $Pb{I}_4$ doesn't ?

• A. because Iodine has electronegativity value
• B. because $I^{-}$ is a strong reducing agent
• C. because $I_2$ is a gas
• D. because Iodine has large size

Answer 1

The correct option is B because $I^{-}$ is a strong reducing agent

$Pb{I}_4$ on dissociation form $I^{-}$ which is strong reducing agents. it get oxidised to $I_2$ and reduce $P{b}^{4+}$ to $P{b}^{2+}$ in both the cases. There is no such scenario in case of $PbC{l}_4$ which justifies its existence.