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Byju's Answer
Standard XII
Chemistry
Oxidation States of Actinides
Why Sm+2 io...
Question
Why
S
m
+
2
ions in solution are good reducing agent but an aqueous solution of
C
e
+
4
is a good oxidising agent?
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Solution
Both
S
m
2
+
and
C
e
4
+
are belonging to landanold series in which
the
+
3
oxidation state is the must stable. Thus, both the ions
tend to acquire
+
3
oxidation state.
C
e
+
does so by
undergoing reduction and thus, a good oxidising agent
S
m
2
+
ions
undergo oxidation to acquire stable state and thus acts
as a reducing agent.
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Similar questions
Q.
C
e
4
+
is a good oxidising agent while
S
m
2
+
is a good reducing agent. Why?
Q.
Which of the following ions is a good oxidising agent?
Q.
Following are the transition metal ions of
3
d
series:
T
i
4
+
,
V
2
+
,
M
n
3
+
,
C
r
3
+
(Atomic numbers:
T
i
=
22
,
V
=
23
,
M
n
=
25
,
C
r
=
24
)
Answer the following:
(i) Which ion is most stable in an aqueous solution and why?
(ii) Which ion is a strong oxidising agent and why?
(iii) Which ion is colourless and why?
Q.
Why alkali metals are good reducing agents?
Q.
Identify the oxidising and reducing agents in the reaction:
Zn + CuSO
4
→ Cu + ZnSO
4
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