Why yellow precipitate formed when aqua solution of lead sulphate is added to an aqueous solution of potassium iodide

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Solution

1. The yellow precipitate is due to the formation of lead iodide.
2. The reaction is as follows :

PbSO₄(aq) + 2 KI (aq) $\to P b I_{2} + K_{2} S O_{4}$

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Question 13

In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?

(a) Lead sulphate (insoluble)
(b) Lead acetate
(c) Ammonium nitrate
(d) Potassium sulphate

Q. When mercuric iodide is added to an aqueous solution of potassium iodide:

Q. 13. In the double displacement reaction between aqueous potassium
iodide and aqueous lead nitrate, a yellow precipitate of lead iodide
is formed. While performing the activity if lead nitrate is not
available, which of the following can be used in place of lead
nitrate?
(a) Lead sulphate (insoluble)
(b) Lead acetate
(c) Ammonium nitrate
(d) Potassium sulphate

What is the coordination entity formed when excess of aqueous KCN is added to an aqueous solution of copper sulphate? Why is it that no precipitate of copper sulphide is obtained when $H_{2} S (g)$ is passed through this solution?

Q. Assertion :"A golden yellow precipitate of lead iodide is formed when colourless lead nitrate solution is mixed with colourless solution of potassium iodide." So, it is a chemical change Reason: Formation of new products in the reaction with the precipitate indicates a chemical change

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Why yellow precipitate formed when aqua solution of lead sulphate is added to an aqueous solution of potassium iodide

1. The yellow precipitate is due to the formation of lead iodide. 2. The reaction is as follows : PbSO​4(aq) + 2 KI (aq) → PbI2 + K2SO4

1. The yellow precipitate is due to the formation of lead iodide.
2. The reaction is as follows :

PbSO₄(aq) + 2 KI (aq) $\to P b I_{2} + K_{2} S O_{4}$